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14x^2+5x=6
We move all terms to the left:
14x^2+5x-(6)=0
a = 14; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·14·(-6)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*14}=\frac{-24}{28} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*14}=\frac{14}{28} =1/2 $
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